ismailmohamad
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yaaaaa.. tnkiu jagajaga..
ade 2 punca x
ade 2 punca x
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x = 2 ----> i
x(x-1) = 2(x-1) ------> ii
pendapat aku la kan
aku xnampak sebarang kesilapan kt soalan ni
bila dua2 side ko darab ngn x-1 makna nye x dah ade dua value
iaitu x=2, x=1
satu lg step ke-5
x(x-2)=x-2
x(x-2)=(x-2)1
tu pasal dapat x=1
kalo ikot buku teks, soalan mcm ni kene susun dlm bentuk ax2+bx+c=0 baru cari solution
so x^2-x=2x-2
patut jd x^2-3x+2=0
(x-1)(x-2)=0
so x=1,x=2
so x mmg ade dua value, bukan maknya 1=2
cube nih lak..
step 1. pusing serentak benti bile 4min abih
jadik 7min = 4min/3min ---- 4min = 0
step 2. pusing serentak tapi ikut 3 min..
jadik 7min = 0 ------- 4min = 3min/1min
step 3. pusing serentak seminit..
jadik 7min = 6min/1min ------- 4 min = 0
step 4.. pusing yg 7min tu dapat 1 min
==================================================================
step 1 = 4min
step 2 = 3min
step 3 = 1min
step 4 = 1min
9min..
akkkhiirrrrrrrnnnyaaaaaaaaaa
yahuu.. puas puas..
cube nih lak..
step 1. pusing serentak benti bile 4min abih
jadik 7min = 4min/3min ---- 4min = 0
step 2. pusing serentak tapi ikut 3 min..
jadik 7min = 0 ------- 4min = 3min/1min
step 3. pusing serentak seminit..
jadik 7min = 6min/1min ------- 4 min = 0
step 4.. pusing yg 7min tu dapat 1 min
==================================================================
step 1 = 4min
step 2 = 3min
step 3 = 1min
step 4 = 1min
9min..