Santai masalah maths

[mohad]

senang2 pown salah..

yang penting berani mencuba...

 

[ownz]

http://www.mathsisfun.com/operation-order-bodmas.html

 

[khairuls]

soalan salah tulis ni.

 

[hilmi_4601]

soalan 1

6÷2(1+2)=?

soalan 2

4-1+2=?

kene satelkn bahgian bracket dahulu
6/2(3) =
6/6 = 1

sama jugak guna cara ni

6/2(3)=
3/1(3) = 1 jugak

kalau x satel bracket pun sama jugak jwpn

6
----
2x(1+2)

3
----
1x(1+2)

3
---= 1
3


soalan no 2
kut mane pun 5 la

 

[tokekapal114]

Soalan 1: 9
Soalan 2: 5

 

[epi_san]

6÷2(1+2)=?
6÷2+4=?
3+4=7

mana boleh jadi 4?

 

[epi_san]

kene satelkn bahgian bracket dahulu
6/2(3) =
6/6 = 1

sama jugak guna cara ni

6/2(3)=
3/1(3) = 1 jugak

kalau x satel bracket pun sama jugak jwpn

6
----
2x(1+2)

3
----
1x(1+2)

3
---= 1
3


soalan no 2
kut mane pun 5 la

kene settlekan braket dlu dah betul..
tapi antara bahagi dan darab kena kira mana dekat depan..
jadi jawapan 9
6/2(3) =
3(3) = 9

 

[hilmi_4601]

kene settlekan braket dlu dah betul..
tapi antara bahagi dan darab kena kira mana dekat depan..
jadi jawapan 9
6/2(3) =
3(3) = 9

so aku dah dpt jwpn.. so yg mane pegang 1 tu kira salah bg aku..


let say jwpn korg 9

so coefficient dia kite dah tau.. variable pun dah tau..
assume (1+2) = x ; so kita tau.. x =3

try to prove the answer 9 is correct.. x must be equal to 3

6/2(x) = 9
6= 9*2x
6= 18x
x= 3 #proven


6/2(x) = 1
6 = 6x
x = 1 wrong, x not equal to 3

ni explanation tuk yg dpt terima jwpn dia 9.. aku pun x percaya jugak.. tp bile buat equation ni.. aku pegang jwpn dia 9.. hahah

 

[ober9]

hukum matematik...kurungan lebih utama pastu darab bahagi (kiri ke kanan) pastu baru tambah tolak (pun kiri ke kanan)...skulah dulu kan mcm tu.

 

[Zordeck]

soalan 1

6÷2(1+2)=?

Dlm bentuk pekali, boleh dihuraikn mcm ni
=6/(2+4)
=6/6
=1

=6/2(3)
=6/6
=1

=6/2(1+2)
=3/1(3)
=3/3
=1



soalan 2

4-1+2=?
=5

+ dan - mestila diselesaikn yg mana dtg dulu.

kalau bercampur2 + - x /, selesaikn x dan /,

kalau ada kurungan, mestila diselesaikan kurungan dahulu